0=-5m^2-55m-150

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Solution for 0=-5m^2-55m-150 equation:



0=-5m^2-55m-150
We move all terms to the left:
0-(-5m^2-55m-150)=0
We add all the numbers together, and all the variables
-(-5m^2-55m-150)=0
We get rid of parentheses
5m^2+55m+150=0
a = 5; b = 55; c = +150;
Δ = b2-4ac
Δ = 552-4·5·150
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-5}{2*5}=\frac{-60}{10} =-6 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+5}{2*5}=\frac{-50}{10} =-5 $

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